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3x^2+35x-7.7=0
a = 3; b = 35; c = -7.7;
Δ = b2-4ac
Δ = 352-4·3·(-7.7)
Δ = 1317.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{1317.4}}{2*3}=\frac{-35-\sqrt{1317.4}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{1317.4}}{2*3}=\frac{-35+\sqrt{1317.4}}{6} $
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